0=-0.1x^2+103x-3000

Solution for 0=-0.1x^2+103x-3000 equation:

0=-0.1x^2+103x-3000

We move all terms to the left:

0-(-0.1x^2+103x-3000)=0

We add all the numbers together, and all the variables

-(-0.1x^2+103x-3000)=0

We get rid of parentheses

0.1x^2-103x+3000=0

a = 0.1; b = -103; c = +3000;
Δ = b2-4ac
Δ = -1032-4·0.1·3000
Δ = 9409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9409}=97$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-103)-97}{2*0.1}=\frac{6}{0.2}
=30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-103)+97}{2*0.1}=\frac{200}{0.2}
=1000
$